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Above 64GB you need registered RAM increasing the latency. So as you increase bandwidth you reduce program speed. Higher frequency results in more heat. We a
by spintin 3y ago
Above 64GB you need registered RAM increasing the latency.
So as you increase bandwidth you reduce program speed.
Higher frequency results in more heat.
We are fast approaching the need for a Wii like Broadway architecture where the program is running in "fast" SRAM and the data is on "slow" DDR.
- lmz 3y agoThe 7800X3D already has 96MB of L3. Surely that's enough for a lot of programs.
- deleted 3y ago[deleted]
- spintin 3y agoYes, but the cost in terms of watt and manufacturing are not scalable. Also most programs have cache-misses.
- _a_a_a_ 3y agoWhy not have a 'pin-to-cache' functionality then.
- smolder 3y agoWhat would it do when you pin more things than your cache can hold? Trigger an interrupt? It basically becomes another memory layer you'd need to manage.
- _a_a_a_ 3y agoWell duh. How is using SRAM going to be any different when you run out of that?
- smolder 3y agoI was not here arguing in favor of explicitly tiered memory. The implied answer to your original question, "why not have a pin to cache functionality?" is that it's effectively the same as having another OS managed memory layer, which is bad since it complicates the architecture. I'll take some cache misses over having to manage it explicitly.
- AnthonyMouse 3y agoNot only that, if you had enough cache to fit everything then there wouldn't be cache misses, and if you didn't, cache misses are pretty unavoidable. It's like the existing APIs for pining things in memory so they can't get paged out. They have very specific uses and normal programs generally don't use them and shouldn't.
- kimixa 3y agoMuch of the cache "management" can be done with specialist load/store instructions that skip the cache rather than being OS managed like a mapping.
- Const-me 3y agoThe higher levels of the stack, be it hardware or software, need to make sure that never happens. That’s how GPUs are doing that. Each thread group can use a limited amount of SRAM, programs declare in advance how many bytes they need. Then in runtime the scheduler who dispatches tasks to cores enforces that limit by never dispatching too many thread groups on each core.
- foobiekr 3y agoThey certainly have this. A lot of embedded boot loaders run entirely from cache until they can bring main memory up and check it.
- anonymousDan 3y agoSorry can you explain what registered RAM is and why it increases latency?
- kimixa 3y agoRegistered memory has a buffer for communication between the dram and the memory controller. So the DDR bus is attached to an intermediate buffer chip, rather than directly to the dram chips on the DIMM. This can give better electrical characteristics of the bus, as the buffer chip to the DIMM connector can have simplified routing and higher power signaling without putting more load on the DRAM chips, and the buffer chip design being focused on this interface signaling rather than compromising between that and the actual DRAM cells. It's a bit more expensive, being an extra chip on each DIMM, and has a latency penalty, as the buffer chip means everything on the DDR bus is effectively 1 clock behind what the DRAM chips themselves provide. But it's often necessary if you have a large number of DIMMs on a single channel or very long traces required for packing lots of DIMMs around a CPU, as that increases the electrical capacitance and noise of each path, which many DRAM chips can struggle to drive, especially at higher speeds. As dram chip density increases you can get higher capacities without the longer bus traces and more DIMMs per channel that might require registered ram, there's nothing "fundamental" about 64gb needing registered ram, and you are already seeing 48gb DDR5 DIMMs that can work on consumer platforms, which often have no issues running 4 DIMMs without registered ram.
- King1st 3y agoDDR5 chips are already semi-buffered. It was part of the major changes from DDR4 to DDR5.
- deleted 3y ago[deleted]