3 ms·
Promotional to the number of _edges_. Edges are proportional to the square of the number of nodes, so the value of the network overall is proportional to the sq
by amomchilov 3y ago
Promotional to the number of _edges_. Edges are proportional to the square of the number of nodes, so the value of the network overall is proportional to the square of the nodes.
Think of it this way, for every new user added to the network:
* the new user is enriched proportional to the number of existing users
* every existing user is enriched by the 1 new user
This double-counting is what gives it the quadratic growth.
- atleta 3y agoYep. That's what I was saying too. The first line of my comment quotes the GP and I was correcting that.