3 ms·
Nope. 2^64 is the number of tries needed for a 50% chance of a collision between two of the tries. You don't have to stay poorly read on this, and groundlessly
by gojomo 3y ago
Nope. 2^64 is the number of tries needed for a 50% chance of a collision between two of the tries. You don't have to stay poorly read on this, and groundlessly allege wrongness:
https://auth0.com/blog/amp/birthday-attacks-collisions-and-password-strength/ https://auth0.com/blog/amp/birthday-attacks-collisions-and-p...