3 ms·
Contrary to what's in the paper, I'm pretty sure IMUL-by-constant is in fact useful, since you can use subtraction: x * (a - b) === x * a - x * b and this a
by o11c 3y ago
Contrary to what's in the paper, I'm pretty sure IMUL-by-constant is in fact useful, since you can use subtraction:
x * (a - b) === x * a - x * b
and this applies even when losing the top half.