4 ms·
have anyone try to do bonding? 5 x 10 Mbps = 50 Mbps over 1km
by asdz 3y ago
have anyone try to do bonding? 5 x 10 Mbps = 50 Mbps over 1km
- notpushkin 3y agoIf you do directional antennas, and I'm not sure how far away you'd have to place them for signals not to interfere with each other. Nice idea tho.
- TickleSteve 3y agoYou would have to ensure each bonding-channel was on a separate RF-channel, otherwise instant collisions.
- zoobab 3y agoIf you can set different fixed channels on different transmitters, you could use Multipath-TCP routers to aggregate multiple routers: https://github.com/Ysurac/openmptcprouter https://github.com/Ysurac/openmptcprouter https://www.openmptcprouter.com/ https://www.openmptcprouter.com/ I mentored the port of MPTCP to OpenWRT years ago, and OpenMPTCPRouter took some of this work in their port.