Ah, of course, you're right. Thanks for pointing that out! I didn't really think about it at the time, but the equation you end up with if you use the accelerat

Ah, of course, you're right. Thanks for pointing that out! I didn't really think about it at the time, but the equation you end up with if you use the acceleration approach results in a v^2, which makes sense when you consider that the equal energy dissipation approach is equivalent.