4 ms·
I don't think there is any JIT on GPU and all the code has to go through a host-side kernel call so it should be able to protect the register I guess?
by flakiness 3y ago
I don't think there is any JIT on GPU and all the code has to go through a host-side kernel call so it should be able to protect the register I guess?
- saagarjha 3y agoThe kernel cannot protect against this, in fact the attackers have full read/write control and code execution capabilities to mount this attack. The fix is blocking this range from being mapped using features that are more powerful than the kernel.