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A strong hash is already difficult to collide. Your algorithm for representation doesn't have to map similar bytes or byte sequences to similar images, but that
by Avamander 3y ago
A strong hash is already difficult to collide. Your algorithm for representation doesn't have to map similar bytes or byte sequences to similar images, but that's just a mapping not really a "hard-to-collide process".
- remram 3y ago> A strong hash is already difficult to collide I don't understand. The whole point of the article is that this isn't true.