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Here's some Haskell code I really like, and I think it would be far less nice in Python: replicateM 10 . forkIO . forever $ do .. Which is basically the
by Peaker 15y ago
Here's some Haskell code I really like, and I think it would be far less nice in Python:
replicateM 10 . forkIO . forever $ do
..
Which is basically the same as:
replicateM 10 (forkIO (forever (do ..)))
replicateM 10 executes its code block argument 10 times. forkIO executes its code block argument in a new thread. forever loops forever.
So this line basically creates a thread pool with 10 threads, all infinitely executing the given code block.
How would you solve this in Python?
- Goladus 15y ago> How would you solve this in Python? The question is how does codeblocks solve this problem in Python, not how does Haskell solve this problem in Haskell.
- Peaker 15y agoHypothetical Python: times(10, forkIO(forever(block: ... )))
- Goladus 15y agoThat's not what codeblocks does, though. You use a with statement and a new operator (<<). Then use indentation for the blocks. It doesn't look like you're passing a block to a function. The result is quirky code that will be hard to trace and sort out if you don't already know what's happening.
- Peaker 15y agoOh, I thought you meant code blocks in general, not the particular OP "codeblocks"... Sorry. I'm not sure that codeblocks actually solves the problem.