3 ms·
Ah, that is a very good reason indeed! At least for projecting from 2D to 1D the gaussian is the only distribution with this property. The functional equation
by enriquto 3y ago
Ah, that is a very good reason indeed! At least for projecting from 2D to 1D the gaussian is the only distribution with this property. The functional equation g(x)g(y)=g(√(x^2+y^2))g(0) determines the gaussian up to a constant.
- T-A 3y agoAlso, their derivative is just a multiplication (if normalized) or two (if not). https://hannibunny.github.io/orbook/preprocessing/04gaussianDerivatives.html https://hannibunny.github.io/orbook/preprocessing/04gaussian...