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> 0 is always going to be a special case for division in real numbers. Right — because it’s impossible to have an inverse of zero multiplication. Eg, 0 = 0 +
by zmgsabst 3y ago
> 0 is always going to be a special case for division in real numbers.
Right — because it’s impossible to have an inverse of zero multiplication.
Eg, 0 = 0 + 0 -> 1 = 1 + 1 -> 0 = 1 if you have a multiplicative inverse to 0, and hence you have collapsed your entire system to a single value.
These are students we’re still teaching that basic algebraic structure to — that it’s not possible to have a multiplicative inverse to zero.
Calling that a “convention” is wrong.