3 ms·
A gradient is defined by dy/dx. And it's associated with lines. If you have gradient=2, you'll have a line that goes through origin and (1,2). If you increas
by Charon77 3y ago
A gradient is defined by dy/dx.
And it's associated with lines.
If you have gradient=2, you'll have a line that goes through origin and (1,2).
If you increase the gradient, it'll decrease the apparent 'dy'. You do it until the line becomes vertical, equivalent of dy=0. A vertical line is a valid object, but mathematically, it's no longer a function. You might say your math breaks describing the thing so you'll need a different math.
- zmgsabst 3y agoThat’s exactly the point: we want division to model inverses of multiplication, but an inverse requires a 1-1 relationship. What the vertical line tells us is that division by zero can’t map to a unique value — it has to give us back the whole set. So we can discuss division by zero in the contexts of inverse maps, but there’s no way to have a function that inverts multiplication by zero. Small technical note: I think you mean ‘dx=0’.