4 ms·
Why doesn't it make sense to use in that case?
by meisel 3y ago
Why doesn't it make sense to use in that case?
- bee_rider 3y agoThe dimensions of (A-UBU’) are the same as the dimensions of A. After you apply Woodbury, you have inv(A) - (other stuff) So, it only makes sense if A is much easier to solve than (A-UBU’).