And thanks to 1/e being 0.367, in Pokemon Go when I catch 1000 Pokemon and each of them has a 1 in 1000 chance of being shiny, I have a 36.7% chance of having z

And thanks to 1/e being 0.367, in Pokemon Go when I catch 1000 Pokemon and each of them has a 1 in 1000 chance of being shiny, I have a 36.7% chance of having zero shinies among them, or approximately a 63% chance of the reciprocate, AKA having at least 1 shiny among them. 1000 is arbitrary of course, but the bigger the number the closer to 1/e. See "Bernoulli trials"