> Furthermore, in Julia the varargs tuple x will have to be > processed without the convenience of Matlab's nargin > function. I genuinely don't get that.

> Furthermore, in Julia the varargs tuple x will have to be > processed without the convenience of Matlab's nargin > function. I genuinely don't get that. nargin is equivalent to length(x) in this scenario, and Julia's overall handling of default/variable arguments seems significantly more convenient than MATLAB's if nargin < 5 foo = 21; end preambles.