3 ms·
There are other models of the two that don't require the geometric product at all. The rest of linear algebra doesn't need it, and recasting all of it in terms
by ajkjk 3y ago
There are other models of the two that don't require the geometric product at all. The rest of linear algebra doesn't need it, and recasting all of it in terms of a frankly terrible operation is not helpful for intuition.