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I don't really get it. Why is { P0:r0 = 1; P1:r0 = 1 } not an allowed final state? What code code could the compiler generate that would definitely prevent the
by deadbeeves 3y ago
I don't really get it. Why is { P0:r0 = 1; P1:r0 = 1 } not an allowed final state? What code code could the compiler generate that would definitely prevent the threads from interleaving their loads and stores on any given architecture?
- xKingfisher 3y agoI think it's just a very confusing, hard to use correctly behavior. And according to the article, very bug prone in implementations. In the example given, the result is that both writes happened before both reads, which directly contradicts the source. There's a valid explanation for why it happens, but it's still paradoxical. I remember at work a C++ standards committee member was giving examples of atomic and how to use them safely with different memory models, when someone pointed out his toy example for relaxed order was wrong. It took 5 people debating for a week to figure out what a safe/correct behavior would be. For a 10 line sample class. As times your second question, the article recommends Hans Boehm's proposal to add a no-op conditional branch after the read. I guess it forces the load to be resolved and enforces a sequenced-before behavior on the individual threads. So at least one read must resolve before one write in the example.
- twoodfin 3y agoYes, relaxed memory semantics are exceedingly difficult to reason about. Hard to believe this is news to the C++ standards committee. I find the premise of this article confusing, and assume it must be because I’m missing something crucial—obviously Hans Boehm knows what he’s talking about. Why do (opt in!) relaxed semantics need to be fixed?
- dataflow 3y ago> relaxed memory semantics are exceedingly difficult to reason about People say this but I don't understand how? They're basically just like ordinary variables. Except even better, because you can use them from multiple threads. And it's guaranteed that a given thread will only ever see values that were actually written by the program (like it's guaranteed the compiler won't introduce spurious writes during optimization). There's no ordering guarantee, just like there's no ordering guarantee across threads for ordinary variables. If relaxed atomics are too hard then aren't ordinary variables too hard? You can certainly use them in a way that's confusing, but that's not because they're themselves complicated - it's because you're writing confusing code. You can do that in a single thread too, with ordinary variables. It's not specific to relaxed atomics. In fact, in my experience, the most confusing atomics are the sequentially consistent ones! I never know when I need to use them in practice vs. acquire/release.
- twoodfin 3y agoThere's no ordering guarantee, just like there's no ordering guarantee across threads for ordinary variables. This is what makes them hard to reason about. C++ makes “as if” ordering guarantees within a single thread trivial: If you can observe things happening out of the order in which your defined-behavior code sequenced them, you have a bug in your compiler or your CPU. Relaxed ordering (on purpose) throws out all implicit sequencing guarantees when threads observe each other. My confusion is that I believed this was all well-understood by implementers and programmers decades ago. That relaxed is harder than sequential to get right was as true on the Alpha as it is on modern ARMs. But this article seems to suggest what should be obvious consequences of relaxed semantics are unexpected & undesirable for C++!
- dataflow 3y ago> This is what makes them hard to reason about. [...] I think we're speaking past each other. You're implicitly assuming there is some piece of code using atomics, and you're saying it's harder to reason about its behavior when the atomics are made to be relaxed (versus, say, sequentially consistent). That's true enough, but it misses my point. I'm coming at this from the opposite direction: I have certain kinds of atomics available, and then I'm using them to write the code. In such a scenario, it's quite easy to distinguish between "I might care about ordering" vs. "I don't care about ordering". In the first case, you probably shouldn't use relaxed atomics - good luck figuring out what to use, it may very well be tricky. If you insist on using relaxed atomics for those, it will definitely be tricky to get it right if it's at all possible, but that's when you should avoid relaxed atomics if at all possible. In the latter case, you should use relaxed atomics, and it's not tricky because you already know ordering doesn't matter. Example: relaxed atomics are trivial to reason about in single-writer situations that aren't signaling any kind of event. Like when a worker is just trying to report progress to the foreground UI with minimal overhead. In this example, the writer (which is on a background thread) simply loads its progress indicator, adds 1, then stores back the variable. There isn't even a need for an atomic RMW, let alone any ordering. The worst case is the user will see "100% done" a few milliseconds too early, which is a non-issue (and already bound to happen due to rounding etc. anyway). Using relaxed atomics doesn't introduce any complexity in such a situation; it's basically exactly what you'd expect from ordinary variables without write-tearing. You run into problems if you try to depend on the "100% progress" indicator to mean "everything is finished" (so you can, say, clean up data structures), but at that point you clearly need ordering and shouldn't use a relaxed atomic to begin with; you'd want release semantics (or stronger), and those are trickier. > My confusion is that I believed this was all well-understood by implementers and programmers decades ago. I definitely agree with this part. I didn't think in 2023 I would read that programmers are shocked that relaxed atomics can be reordered. That's... their entire point. It's like being shocked that compilers propagate constants during optimization.
- dataflow 3y agoYeah I don't understand it either. There's no dependency between the load and store, so there's no inherent ordering. The entire point of relaxed atomics is to let you reorder them freely - otherwise, why aren't you using acquire/release or such?
- gpderetta 3y agoMy understanding is that actual hardware is stronger than C++11 relaxed atomic, but weaker than the revised memory model. The revised memory model closes some theoretical holes in C++11 (for example out-of-thin-air values that don't happen on actual hardware) so it is desirable for some people especially those trying to prove the correctness of compiler transformations, while others do not want to add additional overhead unless necessary. The question is whether there are programs and optimizations that care.