2 ms·

USB defaults to 5V, so depending on how much current you want to draw you might not even need a trigger module.

• stavros 3y ago
  You're right, I guess I might as well just get some straight breakouts for a USB-C for the 5V case, but then I'll be limited to half an amp, which is probably fine for my uses, I guess.
  • lxgr 3y ago
    USB-C supports up to 3A without PD, using only (I believe) resistors/voltages to communicate the limit. That's what many simple early USB-C chargers used to do in order to supply 15W without full PD signalling.
    • stavros 3y ago
      I didn't realize that, thanks!
• p1mrx 3y ago
  USB-C defaults to "off", so a 5V PD trigger would be a sensible product. It just needs a couple resistors, no chip.
  • Kirby64 3y ago
    There’s no such thing as 5V PD unless you mean 5V 5A, fyi. PD is an optionally supported standard of USB-C and the resistors are not part of PD, just the standard USB-C spec.
    • p1mrx 3y ago
      You are technically correct, in that using resistors to trigger 5V would fall under "USB Type-C Current" rather than "USB Power Delivery". But what would you call such a product, other than "5V PD trigger"?
      • joshspankit 3y ago
        5V USB-C board