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Lost me two paragraphs in, due to gross inaccuracy: > Intel 8088 : 8/16-bit microprocessor — 8-bit registers with a 16-bit data bus. Uhh...8088 is 16-bit C
by dmitrygr 3y ago
Lost me two paragraphs in, due to gross inaccuracy:
> Intel 8088 : 8/16-bit microprocessor — 8-bit registers with a 16-bit data bus.
Uhh...8088 is 16-bit CPU. Its external bus is 8-bits wide to save on pins...
It does not get better further in:
> 20-bit memory addressing range — supports 640kB of RAM.
It supports 1MB of addressable space, which the system integrator may allocate as they desire. 640kB is something that PCs did, but apple was in no way tied to..
- userbinator 3y agoIndeed. That description of 8-bit/16-bit is applicable to the 8080/8085/Z80 family.
- johnklos 3y ago> Intel 8088 : 8/16-bit microprocessor — 8-bit registers with a 16-bit data bus. > Uhh...8088 is 16-bit CPU The 8086 / 8088 have eight registers, four general ones (AX, BX, CX, DX) which are made up of two 8 bit registers (AL, AH, BL, BH, CL, CH, DL, DH), so it's both not completely incorrect about 8 bit registers (although I'd agree that it's misleading to say that) but definitely incorrect about the 16 bit data bus.
- dmitrygr 3y agoBy that logic, go ahead and call your 64-core AMD threadripper an eight bit processor too. Cause it still does that…