4 ms·
I haven't heard of this before, so I might be wrong, but I don't think it makes finding collisions any harder. It introduces expotentially many collisions in le
by IsTom 15y ago
I haven't heard of this before, so I might be wrong, but I don't think it makes finding collisions any harder. It introduces expotentially many collisions in length of pepper. For example let's take xyzw and abcd such that h(xyzw) = h(abcd), now if you take peppered hash with length of pepper one you get hp(yzw) = hp(bcd).