3 ms·
Good point, I was wrong. However, it can also happen that the factors are not gaussian, and still the multiplication would follow a lognormal distribution by th
by alexmolas 3y ago
Good point, I was wrong. However, it can also happen that the factors are not gaussian, and still the multiplication would follow a lognormal distribution by the CLT. So saying that "if you condition on enough factors the distribution will be normal" requires the assumption that the factors are normally distributed.