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No. In the latter case the "upstream source code" is the key, and the compiler is the functional transformation under scrutiny. Think of a triangle where we wa
by nonrandomstring 3y ago
No. In the latter case the "upstream source code" is the key, and the
compiler is the functional transformation under scrutiny. Think of a
triangle where we want two fixed (trustworthy) points to ascertain
the third. Here our trusted principles are a repository (better
multiple repositories) of source code, and a deterministic executable
from someone who has already compiled using a known good compiler.