4 ms·
We can also look at it from the perspective of the geometric distribution: if the P(Crash) = 1/200k for each mile driven there is around a 36% chance that the c
by Homunculiheaded 15y ago
We can also look at it from the perspective of the geometric distribution: if the P(Crash) = 1/200k for each mile driven there is around a 36% chance that the car would have made it 200k miles without a crash.