3 ms·
Perhaps. However the standard deviation for a Bernoulli trial is sqrt(Npq) where p = 0.00049 and q = 1 - p. The two trials are not significantly different.
by jgoodwin 15y ago
Perhaps. However the standard deviation for a Bernoulli trial is sqrt(Npq) where p = 0.00049 and q = 1 - p.
The two trials are not significantly different.