4 ms·
> requiring 4x the flow rate to do the same work. I strongly suspect that this is incorrect. A given amount of oxygen and fuel releases the same amount of ener
by m3047 3y ago
> requiring 4x the flow rate to do the same work.
I strongly suspect that this is incorrect. A given amount of oxygen and fuel releases the same amount of energy at any (reasonable?) pressure. 4x oxy (and fuel) --> 4x energy... this is the principle of turbochargers and superchargers (although the limiting factor is compression).
Interestingly, and paradoxically, I suspect that at an appreciable depth you mitigate the "air pump" effect and you don't need the compression stroke (or as much of one) to achieve a particular fuel mixture density prior to ignition so you'd lose "compression braking" and gain some efficiency.
(I also suspect that what happens if your vessel implodes and you're suddenly subject to 6,000psi is that the now superheated oxygen reacts with any oxidizable material at hand in an explosive exothermic reaction.)
- itishappy 3y agoI think we're both right and describing different things. The air in the engine will be 4x as dense, but the flow rate will be the same. The air in the tank cannot change density, and will therefore have a 4x higher flow rate. The result is that storage is worth less strokes/breaths at depth.