4 ms·
> It will be cheaper though, which is the important part. Indeed. For a long time, new nodes could be read as: more ICs/wafer = lower cost/IC = lower cost/tran
by RetroTechie 3y ago
> It will be cheaper though, which is the important part.
Indeed. For a long time, new nodes could be read as: more ICs/wafer = lower cost/IC = lower cost/transistor in those ICs. Or bigger ICs with more transistors.
Leaving it up to designers to choose between cheaper/smaller/lower power, or use extra transistors to achieve higher performance at similar cost/IC.
Maybe that lower cost/transistor 'law' doesn't hold anymore for these latest nodes? Or not as much as it used to?
Not saying Moore's law is dead! But it talks transistors/IC. Not so much about the cost of those transistors.
So maybe we're seeing some decoupling here between Moore's law & cost/transistor gains for newer nodes? If so, that would certainly affect market segmentation between products built on older vs. built on newer nodes. As opposed to the 'newer = better everything' we're used to.
Note this is just speculation on my part.