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> Anyway, the point is that the halting procedure in its full generality cannot exist, while each individual busy beaver number can be solved in theory (even if
by tshaddox 3y ago
> Anyway, the point is that the halting procedure in its full generality cannot exist, while each individual busy beaver number can be solved in theory (even if there’s no algorithm that can list them all).
It's possible to prove the values of certain busy beaver numbers, of course, but that's equivalent to noting that you can prove whether certain TMs halt. For example, it is possible to run every n-state TM long enough that, for each TM, you've either observed it halt or you've proved that it's in an infinite loop. The problem is that, for any TM that you haven't observed halt and you haven't been able to prove it's in an infinite loop, you just gotta keep waiting until one or the other happens. And, critically, you can't know if you'll ever come up with a proof that it's in an infinite loop.
- srcreigh 3y agoYeah. In the most egregious case it could come down to simply listing the numbers that we have proofs for. Another interesting thought is whether we can prove the limit of say ZFC in busy beaver numbers with just ZFC. We have BB(745) limit for ZFC. It would be fascinating if “BB(20) is independent of ZFC” turns out to be independent of ZFC as well.