3 ms·
Anyone who writes a compiler for Go can guarantee such behavior--anything else is a buggy implementation. It works in practice because it's a requirement of th
by compiler-guy 3y ago
Anyone who writes a compiler for Go can guarantee such behavior--anything else is a buggy implementation.
It works in practice because it's a requirement of the implementation.
- felixge 3y agoI guess I’m less worried about the atomic nature of the operation and more about the way the writes become visible. That seems to be entirely hardware dependent?