2 ms·
Exactly. In fact, there will always be some element a in a field¹ for which there is no multiplicative inverse. This is why with boolean algebra, both ⋀ and ⋁ a
by dhosek 3y ago
Exactly. In fact, there will always be some element a in a field¹ for which there is no multiplicative inverse. This is why with boolean algebra, both ⋀ and ⋁ are multiplication operators (for ⋀, T has no inverse; for ⋁, F has no inverse).
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1. To be clear for readers, when KMag and I say, “field,” we’re referring to a specific mathematical construct in which there are + and × operators and symbols 0 and 1, the former being the additive identity and the latter the multiplicative identity.