3 ms·

The difference is that they want to turn a = d(c(b,7)) into a = b |> c(%,7) |> d(%) and I would like to see it turn into a = b,7 ~> c ~> d

by mg 3y ago

gpderetta 3y ago
Does JS have a splat operator? So: a = (b, 7) |> c(*%) |> d(%) Too much operator soup I guess.
- notpushkin 3y ago
  Yeah, it is the ellipsis: a = b |> c(...%, 7) |> d(%) Spaciousness helps here a bit, but still way too many syntax, I agree.
IggleSniggle 3y ago
It took me a moment, but your version is very nice.
notpushkin 3y ago
It feels a bit unnatural to pipe multiple arguments like that in JS, and you could inline them in the first call without losing legibility: a = c(b, 7) |> d(%) It's the arguments added way down the line that are problematic: a = f((e(d(c(b))), 4), 5) a = ((b ~> c ~> d), 4 ~> e), 5 ~> f a = b |> c(%) |> d(%) |> e(%, 4) |> f(%, 5) Smart pipes [1] were a bit nicer about that: a = b |> c |> d |> e(#, 4) |> f(#, 5) Basically you would use # token whenever you wanted an expression and just a function name when you needed to pass a single argument. Best of both worlds IMO. Perhaps it could even be extended for Curry-ish function syntax (although it isn't as obvious): a = b |> c(7) |> d a = d(c(7, b)) Too bad it was withdrawn. [1]: https://github.com/tc39/proposal-smart-pipelines https://github.com/tc39/proposal-smart-pipelines P. S. When studying Haskell on a CS course in school, I used to define exactly the same squiggly arrow operator for my programs :-) x ~> f = f x
- notpushkin 3y ago
  Aside, but there's another kind of syntax possible here: const result = ( await fetch(url) .json() ::Object.keys .map(key => ...) ::new ByteArray );
- oispakaljaa 3y ago
  > P. S. When studying Haskell on a CS course in school, I used to define exactly the same squiggly arrow operator for my programs :-) Haskell base already has the reverse application operator (&) which does the same thing. Not included in the prelude but can be imported from Data.Function. [1] It's defined as: (&) :: a -> (a -> b) -> b x & f = f x Not that there's anything wrong with using your own definitions, just thought I'd point it out! [1] https://hackage.haskell.org/package/base-4.18.1.0/docs/Data-Function.html#v:-38- https://hackage.haskell.org/package/base-4.18.1.0/docs/Data-...
- mg 3y ago
  This: a = f((e(d(c(b))), 4), 5) Seems not to make sense. Replacing c(b) with x we get: a = f((e(d(x)), 4), 5) Replacing d(x) with x we get: a = f((e(x), 4), 5) Replacing e(x) with x we get: a = f((x, 4), 5) What is that?
  - notpushkin 3y ago
    Sorry, messed up parens here. It should have been: a = f(e(d(c(b))), 4), 5) b is passed to c, then the result is passed to d, then to e along with 4 as a second parameter, and finally to f along with 5.
    - mg 3y ago
      a = f(e(d(c(b))), 4), 5) That has 4 opening parenthesis and 5 closing parenthesis. b is passed to c b ~> c then the result is passed to d b ~> c ~> d then to e along with 4 as a second parameter b ~> c ~> d,4 ~> e and finally to f along with 5 b ~> c ~> d,4 ~> e,5 ~> f

The difference is that they want to turn a = d(c(b,7)) into a = b |> c(%,7) |> d(%) and I would like to see it turn into a = b,7 ~> c ~> d

by mg 3y ago

The difference is that they want to turn a = d(c(b,7)) into a = b |> c(%,7) |> d(%) and I would like to see it turn into a = b,7 ~> c ~> d

gpderetta 3y ago

Does JS have a splat operator? So: a = (b, 7) |> c(*%) |> d(%) Too much operator soup I guess.

notpushkin 3y ago
Yeah, it is the ellipsis: a = b |> c(...%, 7) |> d(%) Spaciousness helps here a bit, but still way too many syntax, I agree.

IggleSniggle 3y ago

It took me a moment, but your version is very nice.

notpushkin 3y ago

It feels a bit unnatural to pipe multiple arguments like that in JS, and you could inline them in the first call without losing legibility: a = c(b, 7) |> d(%) It's the arguments added way down the line that are problematic: a = f((e(d(c(b))), 4), 5) a = ((b ~> c ~> d), 4 ~> e), 5 ~> f a = b |> c(%) |> d(%) |> e(%, 4) |> f(%, 5) Smart pipes [1] were a bit nicer about that: a = b |> c |> d |> e(#, 4) |> f(#, 5) Basically you would use # token whenever you wanted an expression and just a function name when you needed to pass a single argument. Best of both worlds IMO. Perhaps it could even be extended for Curry-ish function syntax (although it isn't as obvious): a = b |> c(7) |> d a = d(c(7, b)) Too bad it was withdrawn. [1]: https://github.com/tc39/proposal-smart-pipelines https://github.com/tc39/proposal-smart-pipelines P. S. When studying Haskell on a CS course in school, I used to define exactly the same squiggly arrow operator for my programs :-) x ~> f = f x

notpushkin 3y ago
Aside, but there's another kind of syntax possible here: const result = ( await fetch(url) .json() ::Object.keys .map(key => ...) ::new ByteArray );
oispakaljaa 3y ago
> P. S. When studying Haskell on a CS course in school, I used to define exactly the same squiggly arrow operator for my programs :-) Haskell base already has the reverse application operator (&) which does the same thing. Not included in the prelude but can be imported from Data.Function. [1] It's defined as: (&) :: a -> (a -> b) -> b x & f = f x Not that there's anything wrong with using your own definitions, just thought I'd point it out! [1] https://hackage.haskell.org/package/base-4.18.1.0/docs/Data-Function.html#v:-38- https://hackage.haskell.org/package/base-4.18.1.0/docs/Data-...
mg 3y ago
This: a = f((e(d(c(b))), 4), 5) Seems not to make sense. Replacing c(b) with x we get: a = f((e(d(x)), 4), 5) Replacing d(x) with x we get: a = f((e(x), 4), 5) Replacing e(x) with x we get: a = f((x, 4), 5) What is that?
- notpushkin 3y ago
  Sorry, messed up parens here. It should have been: a = f(e(d(c(b))), 4), 5) b is passed to c, then the result is passed to d, then to e along with 4 as a second parameter, and finally to f along with 5.
  - mg 3y ago
    a = f(e(d(c(b))), 4), 5) That has 4 opening parenthesis and 5 closing parenthesis. b is passed to c b ~> c then the result is passed to d b ~> c ~> d then to e along with 4 as a second parameter b ~> c ~> d,4 ~> e and finally to f along with 5 b ~> c ~> d,4 ~> e,5 ~> f