2 ms·
So… she’s correct in the industrial regime that matters, but technically incorrect in the experimental regime where the energy is not recovered?
by jiggawatts 3y ago
So… she’s correct in the industrial regime that matters, but technically incorrect in the experimental regime where the energy is not recovered?
- Retric 3y agoIf she was talking about very high Q then it wouldn’t be a major issue, but she was specifically referring to the regimes where it was important. Aka energy breakeven and minimum economic viability. It also explains why Q is formulated in terms of energy added to the plasma vs energy gained from fusion which she didn’t understand. This formula for Q ends up being a term in the equation for economic viability, but she attacked it as if such a formulation was misleading. Basically the total energy spent on the facility including cryogenic cooling, pumps, etc matters + Q as defined by fusion experts + fusion output energy + conversion energy lets you find the total net energy gain which you then compare with the cost of the facility to find economic viability. Roughly, [ (Fusion energy) * (1 + 1/Q) * (conversion efficiency) - (Total energy use by facility) ] / (cost per hour of operation) = energy per dollar. There are other ways you can calculate that same number, but they require a lot more details.