4 ms·
Imagine you have a function which transforms nicely under scaling, ie. f(Mx) = M^k f(x) for some b. Then if you have systems where you use x -> Mx regularly, yo
by joe__f 3y ago
Imagine you have a function which transforms nicely under scaling, ie. f(Mx) = M^k f(x) for some b. Then if you have systems where you use x -> Mx regularly, you'll find these functions turn up because they're the ones that respect the symmetry.
Now make M to be a Mobius transformation, so that f((ax + b)/(cx + d)) = (cx + d)^k f(x), where the coefficients are in SL(2,Z) ie. integers with ad - bc = 1. Mobius transformations like this are common.
That's more or less it as far as I'm aware. There's some growth rate condition too, I don't think it's as important to an intuitive understanding as the transformation law.
Disclaimer; my training was in mathematical physics not mathematics. To me, what l wrote here was enough for me to feel like I understand what they are, at least to some basic level.
- fxj 3y agoModular forms can also be viewed as functions in the 2d projective space with a special symmetry: let f(ax, ay) = a^k f(x,y) be a homogeneous function in the plane x,y for a scalar a, then f can also be written as: f(x,y) = f(y*x/y, y) = y^k f(x/y,1) and the symmetry by a matrix transformation in the plane x-> ax + by and y-> cx+dy then transforms the function f as: f(ax+by, cx+dy) = (cx+dy)^k f((ax+by)/(cx+dy),1) now introduce z=x/y and f(x/y,1)=F(z) then F((az+b)/(cz+d)) = (cz+d)^k F(z) Projective spaces are cool ;-) just my 2 ct
- joe__f 3y agoOh yeah that's a nice observation! Protective space in 2D is the same as the Riemann sphere, which is the complex plane with one point added at infinity. I forgot to add to my post that, SL(2) is the symmetry group of the Riemann sphere. So since you often use this as your space in complex analysis, this symmetry transformation is everywhere. So that's one reason why you might expect to see modular forms in lots of places. (At least, that's what I understood, maybe a mathematician would tell you differently.)