4 ms·
Long should be able to do the trick for you? > Long l1 = Long.parseUnsignedLong("17916881237904312345"); Or, just use BigInteger
by capableweb 3y ago
Long should be able to do the trick for you?
> Long l1 = Long.parseUnsignedLong("17916881237904312345");
Or, just use BigInteger