4 ms·
No explanation whatsoever. Why the branch predictor is not "invoked" in the first version of the function?
by zerr 3y ago
No explanation whatsoever. Why the branch predictor is not "invoked" in the first version of the function?
- MauranKilom 3y agoBecause it's most likely using a conditional move.
- distcs 3y agoBut I don't see the post going into investigating this at all. Yes, most likely that is what is going on but I don't understand the point of the OP post is if the real reason of the difference in the branch predictor behavior is not explained.