3 ms·
My napkin says you have 8C on the left and 9C on the right, so your stoichiometry is off. I haven’t tried to check any of the rest. I’m guessing the major erro
by amluto 3y ago
My napkin says you have 8C on the left and 9C on the right, so your stoichiometry is off. I haven’t tried to check any of the rest.
I’m guessing the major error is that the -0.8V is “versus reversible hydrogen electrode ”, so it’s a half-reaction and you need to fill in the correct other half reaction, and there is probably H2 involved. Then you would dig out some free energy values to see how efficient it is.
(I only read the abstract.)
- flakinur 3y agoThx for the catch! Fixed the math using chat gpt :P. Reaction: 3CO2 + 12H2 -> C3H8 + 6O2 Number of moles of electrons (n): n = 3 * 4 = 12 Total charge (Q) in Coulombs: Q = (-395 * 1 * 100 * 3600 * 0.91 / 1000) * 12 * 96485 Voltage (V): V = -0.8 Total energy for given current density: E = Q * V Moles of CO2 in 1 ton: n_CO2 = (1000 * 1000) / 44.01 Total charge for 1 ton of CO2: Q_total = (12 / 3) * n_CO2 * 96485 Adjusted charge considering Faradaic efficiency: Q_adjusted = Q_total * 0.91 Total energy for 1 ton of CO2: E_total = Q_adjusted * V Convert to kWh: E_kWh = E_total * 2.778e-7 E_kWh ≈ 17707.4 kWh
- amluto 3y agohttps://www.engineeringtoolbox.com/co2-emission-fuels-d_1085.html https://www.engineeringtoolbox.com/co2-emission-fuels-d_1085... Gives a specific CO2 emission for propane of 13.8 kg carbon / kWh fuel, so your numbers are at least vaguely credible. But your reaction is devoid of CO2, so talking about tons of CO2 is still odd.
- jwilk 3y ago> 3CO2 + 12H2 -> C3H8 + 6O2 6 O on the left, 12 on the right. 24 H on the left, 8 on the right.