Anyone more if bayes rule can apply? I believe it gives the correct answer P(two boys | atleast one) = P(atleast one boy | two boys) * P(two boys)/P(atleast on

Anyone more if bayes rule can apply? I believe it gives the correct answer P(two boys | atleast one) = P(atleast one boy | two boys) * P(two boys)/P(atleast one boy) = 1*(1/4)/(3/4) = 1/3