3 ms·
I believe it is to make sure that x and y are of comparable types. Comparing pointers of different types generates a warning with GCC. I can be wrong though..
by yan 18y ago
I believe it is to make sure that x and y are of comparable types. Comparing pointers of different types generates a warning with GCC. I can be wrong though..
- babo 18y agoYou are right, it's a compile time argument checking for type equality.