> In the end it boils down to continuations No it does not. > your function Only if you deal exclusively with procedures/functions. With dataflow, that's n

> In the end it boils down to continuations No it does not. > your function Only if you deal exclusively with procedures/functions. With dataflow, that's not the case. You have two filters, and if the first filter detects an error, it just does nothing (i.e it does not pass the value to the second filter). Done. No need for exceptions or continuations, or weird return types.