4 ms·
Yes, this is correct. If you look at the Schwarzschild solution to the Einstein field equations you'll find that there are two apparent singularities: one at t
by antognini 3y ago
Yes, this is correct. If you look at the Schwarzschild solution to the Einstein field equations you'll find that there are two apparent singularities: one at the center of the black hole, and another at the event horizon. However, the apparent singularity at the event horizon is not a true singularity because you can perform a coordinate transformation in which it disappears. Mathematically, this is doing what you describe: going from the reference frame of an external observer to one who is falling into the black hole. To the outside observer you appear to take an infinite amount of time to fall in, but from the perspective of the person falling in, it happens in a finite amount of time.
The other singularity at r = 0 is different, though. It is a true singularity because there is no coordinate transformation you can make in which it disappears.
- angiosperm 3y agoIf the escape velocity from the event horizon is (defined to be) light speed, that seems to mean falling in from indefinitely far away, you would get indefinitely close to light speed (as perceived from at rest outside) at the point when you cross it,.