3 ms·
Some operations have much more complex inverses, in a computational sense, so I don't think it's so simple. The key to showing this is to reduce the problem to
by xvedejas 3y ago
Some operations have much more complex inverses, in a computational sense, so I don't think it's so simple. The key to showing this is to reduce the problem to its inverse: https://en.wikipedia.org/wiki/Reduction_(complexity) https://en.wikipedia.org/wiki/Reduction_(complexity)