> if !e->inuse but e == ent->client->chase_target, the original will loop but yours will exit. No, the continue statement will jump to the test part also for `

> if !e->inuse but e == ent->client->chase_target, the original will loop but yours will exit. No, the continue statement will jump to the test part also for `do' loops: "The continue statement is related to break, but less often used; it causes the next iteration of the enclosing for, while, or do loop to begin. In the while and do, this means that the test part is executed immediately" -- "The C programming language (Second Edition)"