2 ms·
Depending on clock speed of memory. For LPDDR5-6400 which is pretty common. 3200000000(clock) x 2(DDR) x 2(16-bit channel width) x 4(channels) = 51200000000 by
by kcb 3y ago
Depending on clock speed of memory. For LPDDR5-6400 which is pretty common.
3200000000(clock) x 2(DDR) x 2(16-bit channel width) x 4(channels) = 51200000000 bytes/sec or 51.2 GBytes/sec
- vel0city 3y ago16 bits is where you added data width here, so that would be 52 gigabits a second, no? To go to bytes wouldn't we need to divide by 8? And I imagine this commenter talking about 8GB RAM, they're assuming not all 4 channels are populated. So one could imagine two channels being populated, 25.6 Gbit/sec, divide by 8 to get bytes, that's then only 3.2GB/s?