3 ms·

This is only true if the codomain has the relevant structure for vector operations. Functions are more general than vectors.

• robinzfc 3y ago
  Right. Specifically, the codomain needs to be an abelian group. And even that is not sufficient as one needs also an action of the field of scalars on that codomain with the right properties.
  • tprice7 3y ago
    In other words, the codomain needs to be a vector space.