Would that really work? You can chain those functions because they return the same type. For example, filtering a list returns a subset of the list. Any/all re

Would that really work? You can chain those functions because they return the same type. For example, filtering a list returns a subset of the list. Any/all return a Boolean, so the chain would stop there. I also personally think any(x % 5 in range(y)) Is more clear than range(y).any(lambda x: x % 5)