3 ms·
12.0200112_e = e+2+2/e^2+e^-5+e^-6+2e^-7 = 4.99999285804..... so 5 in base e is an infinite sequence of digits starting with 12.020011....
by ez667 3y ago
12.0200112_e = e+2+2/e^2+e^-5+e^-6+2e^-7 = 4.99999285804.....
so 5 in base e is an infinite sequence of digits starting with 12.020011....
- joe__f 3y agoHow many digits do you need to do this for a given transcendental?