4 ms·
Do you really know it breaks Z2 rather than something else? There are plenty of symmetry breaking patterns that correspond to observables which go from <x^2> =
by evanb 3y ago
Do you really know it breaks Z2 rather than something else? There are plenty of symmetry breaking patterns that correspond to observables which go from <x^2> = 0 to (<x^2> ≠ 0 and <x> = ±some mean if you don't tunnel enough).
If it really breaks Z2 and falls into the Ising universality class then you should be able to predict [read: look up] some of the critical exponents before measuring them.
- lucaambrogioni 3y agoThe 1d example certainly breaks Z2, but since the thermodynamics is slightly different, you need to careful. For example, several exponents regulate the scaling with respect to the temperature, but theta is not, strictly speaking, a temperature parameter. We need to do the calculations see.