2 ms·
If you're really slick about it, you even "fix" the Gaussian integral this way. Let é = e^sqrt(2pi), déx = dx/sqrt(2pi), and we have int_{R}(é^(int_0^x(t dét)
by scythe 3y ago
If you're really slick about it, you even "fix" the Gaussian integral this way.
Let é = e^sqrt(2pi), déx = dx/sqrt(2pi), and we have
int_{R}(é^(int_0^x(t dét)) déx)
= int_{R}(e^(sqrt(2pi) x^2/(2 sqrt(2pi))) dx/sqrt(2pi))
= 1/sqrt(2pi) int_{R}(e^(x^2/2) dx)
= sqrt(2pi) / sqrt(2pi)
= 1
- enriquto 3y ago> exp(sqrt(2pi)) Now, this is a number that I don't recall having seen before. The letter é seems strangely fitting for it é = 12.2635111...