2 ms·

I would have naively calculated average error as avg(max( abs(smallest), largest)). so it would be 100 in your case. I'm sure that's not statistically correct b

by glibby 3y ago

I would have naively calculated average error as avg(max( abs(smallest), largest)). so it would be 100 in your case. I'm sure that's not statistically correct but it makes sense to me.