The answer by user 'Blue' on the same thread seems more practical to me. Their answer[1] uses notation that doesn't translate to this messageboard. Perhaps a r

The answer by user 'Blue' on the same thread seems more practical to me. Their answer[1] uses notation that doesn't translate to this messageboard. Perhaps a reordering of their method, using the existing caret notation: b^p = r :: the result from base b with exponent p ^pr = b :: the base giving result r from exponent p br^ = p :: the exponent yielding r with base b [1] https://math.stackexchange.com/a/1158802 https://math.stackexchange.com/a/1158802