2 ms·
The problem is when you sell X bits for $Y, you'll want to keep X as low as possible and Y as high. Now if bits were fully metered they'd have no problem sellin
by adestefan 15y ago
The problem is when you sell X bits for $Y, you'll want to keep X as low as possible and Y as high. Now if bits were fully metered they'd have no problem selling you all they have.